What is the answer to 7(4^x)=4(6^{2x-2}) ?

The answer to 7(4^x)=4(6^{2x-2}) is x=(ln(63))/(2ln(3))

Solve for x: 7(4^x)=4(6^{2x-2})

The solution is x=(ln(63))/(2ln(3))

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7 (4^{x}) = 4 (6^{2 x - 2})

x = \frac{ln ( 63 )}{2 ln ( 3 )}

Decimal Notation

x = 1.88562 \dots

Solution steps

7 (4^{x}) = 4 (6^{2 x - 2})

Apply exponent rules

ln (7) + x ln (4) = ln (4) + (2 x - 2) ln (6)

Solve

ln (7) + x ln (4) = ln (4) + (2 x - 2) ln (6) : x = \frac{ln ( 63 )}{2 ln ( 3 )}

x = \frac{ln ( 63 )}{2 ln ( 3 )}

5 (2^{x}) = 3 (7^{4 x - 4})

7 (2^{x}) = 2 (3^{4 x - 4})

4 (3^{x}) = 3 (6^{3 x - 3})

3^{3 x} = 7^{2 x + 1}

4^{x} = 8

What is the answer to 7(4^x)=4(6^{2x-2}) ?
The answer to 7(4^x)=4(6^{2x-2}) is x=(ln(63))/(2ln(3))
Solve for x: 7(4^x)=4(6^{2x-2})
The solution is x=(ln(63))/(2ln(3))