What is the answer to 2^{x^2-1}=4^{2x+2} ?

The answer to 2^{x^2-1}=4^{2x+2} is x=5,x=-1

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2^{x^2-1}=4^{2x+2}

2^{x^{2} - 1} = 4^{2 x + 2}

x = 5, x = - 1

Solution steps

2^{x^{2} - 1} = 4^{2 x + 2}

Apply exponent rules

x^{2} - 1 = 2 (2 x + 2)

Solve

x^{2} - 1 = 2 (2 x + 2) : x = 5, x = - 1

x = 5, x = - 1

\frac{27}{( 3 ^{(1 - 3 x)} )} = 9

4 = 1 6^{x}

4^{(2 x^{2} + x - 6)} = 1

What is the answer to 2^{x^2-1}=4^{2x+2} ?
The answer to 2^{x^2-1}=4^{2x+2} is x=5,x=-1
Solve for x: 2^{x^2-1}=4^{2x+2}
The solution is x=5,x=-1