What is the answer to (27)/((3^{(1-3x)))}=9 ?

The answer to (27)/((3^{(1-3x)))}=9 is x=0

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(27)/((3^{(1-3x)))}=9

\frac{27}{( 3 ^{(1 - 3 x)} )} = 9

x = 0

Solution steps

\frac{27}{( 3 ^{(1 - 3 x)} )} = 9

Apply exponent rules

- 1 + 3 x = - 1

Solve

- 1 + 3 x = - 1 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

4 = 1 6^{x}

4^{(2 x^{2} + x - 6)} = 1

t, a = p (1 + r)^{t}

What is the answer to (27)/((3^{(1-3x)))}=9 ?
The answer to (27)/((3^{(1-3x)))}=9 is x=0
Solve for x: (27)/((3^{(1-3x)))}=9
The solution is x=0