What is the answer to 32^{3p+2}=16^{p-1} ?

The answer to 32^{3p+2}=16^{p-1} is p=-14/11

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32^{3p+2}=16^{p-1}

3 2^{3 p + 2} = 1 6^{p - 1}

p = - \frac{14}{11}

Decimal Notation

p = - 1.27272 \dots

Solution steps

3 2^{3 p + 2} = 1 6^{p - 1}

Apply exponent rules

5 (3 p + 2) = 4 (p - 1)

Solve

5 (3 p + 2) = 4 (p - 1) : p = - \frac{14}{11}

p = - \frac{14}{11}

3^{2 (x + 1)} - 18 \cdot 3^{x} + 9 = 0

2^{x} - 2^{x - 2} = 3 (2^{13})

3 e^{2 x} = 4.2

4^{x} + 1 = 2^{x + 1}

5^{x} = 3^{x - 1}

What is the answer to 32^{3p+2}=16^{p-1} ?
The answer to 32^{3p+2}=16^{p-1} is p=-14/11
Solve for p: 32^{3p+2}=16^{p-1}
The solution is p=-14/11