What is the answer to 2^x*5^{x-1}=0.01 ?

The answer to 2^x*5^{x-1}=0.01 is x=(ln(0.05))/(ln(10))

Solve for x: 2^x*5^{x-1}=0.01

The solution is x=(ln(0.05))/(ln(10))

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2^{x} \cdot 5^{x - 1} = 0.01

x = \frac{ln ( 0.05 )}{ln ( 10 )}

Solution steps

2^{x} \cdot 5^{x - 1} = 0.01

Apply exponent rules

(x - 1 + 1 + lo g_{2} (5) (x - 1)) ln (2) = ln (0.01)

Solve

(x - 1 + 1 + lo g_{2} (5) (x - 1)) ln (2) = ln (0.01) : x = \frac{ln ( 0.05 )}{ln ( 10 )}

x = \frac{ln ( 0.05 )}{ln ( 10 )}

800 = 25 (2^{t})

2^{x + 2} + 2^{x - 1} - 2^{x - 3} = 70

n, p = \frac{1}{1 0 ^{n}}

2^{2 x + 18} = 3^{x - 12}

e^{x} = 17.8

What is the answer to 2^x*5^{x-1}=0.01 ?
The answer to 2^x*5^{x-1}=0.01 is x=(ln(0.05))/(ln(10))
Solve for x: 2^x*5^{x-1}=0.01
The solution is x=(ln(0.05))/(ln(10))