Solution
solve for
Solution
Solution steps
Apply exponent rules
Solve
Popular Examples
solvefor x,2^x=14solve for 4^x5^{x+1}=12^{2x-1}440=27.5(\sqrt[12]{2})^{n-1}\sqrt[4]{3^x}=\sqrt[3]{9}(x+2)^{x+4}=(x+2)^{x^2+3x+1}
Frequently Asked Questions (FAQ)
What is the answer to solvefor x,2^x=2y ?
The answer to solvefor x,2^x=2y is x=(ln(2y))/(ln(2))