What is the answer to 2^x=5^{x-2} ?

The answer to 2^x=5^{x-2} is x=(2ln(5))/(ln(5)-ln(2))

Solve for x: 2^x=5^{x-2}

The solution is x=(2ln(5))/(ln(5)-ln(2))

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2^{x} = 5^{x - 2}

x = \frac{2 ln ( 5 )}{ln ( 5 ) - ln ( 2 )}

Decimal Notation

x = 3.51294 \dots

Solution steps

2^{x} = 5^{x - 2}

Apply exponent rules

x ln (2) = (x - 2) ln (5)

Solve

x ln (2) = (x - 2) ln (5) : x = \frac{2 ln ( 5 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{2 ln ( 5 )}{ln ( 5 ) - ln ( 2 )}

2 (10)^{x} + 1 0^{x + 1} = 4

67 = 2 1^{x}

y = b + a e^{- x}, x

x, e^{x^{2} + 1} = 5 e^{- x}

4^{3 x - 15} - 64 = 0

What is the answer to 2^x=5^{x-2} ?
The answer to 2^x=5^{x-2} is x=(2ln(5))/(ln(5)-ln(2))
Solve for x: 2^x=5^{x-2}
The solution is x=(2ln(5))/(ln(5)-ln(2))