What is the answer to 7^{1/x}=11^x ?

The answer to 7^{1/x}=11^x is x=sqrt((ln(7))/(ln(11))),x=-sqrt((ln(7))/(ln(11)))

Solve for x: 7^{1/x}=11^x

The solution is x=sqrt((ln(7))/(ln(11))),x=-sqrt((ln(7))/(ln(11)))

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7^{\frac{1}{x}} = 1 1^{x}

x = \frac{ln ( 7 )}{ln ( 11 )}, x = - \frac{ln ( 7 )}{ln ( 11 )}

Decimal Notation

x = 0.90083 \dots, x = - 0.90083 \dots

Solution steps

7^{\frac{1}{x}} = 1 1^{x}

Apply exponent rules

\frac{1}{x} ln (7) = x ln (11)

Solve

\frac{1}{x} ln (7) = x ln (11) : x = \frac{ln ( 7 )}{ln ( 11 )}, x = - \frac{ln ( 7 )}{ln ( 11 )}

x = \frac{ln ( 7 )}{ln ( 11 )}, x = - \frac{ln ( 7 )}{ln ( 11 )}

(2)^{3 x - 1} = 32

3^{(x^{2} + 4 x)} = \frac{1}{27}

4^{2 x - 1} = 5^{x + 2}

e^{(2 x)} - 2 e^{(x)} - 24 = 0

25 6^{- 1} = 1 6^{2 x - 2}

What is the answer to 7^{1/x}=11^x ?
The answer to 7^{1/x}=11^x is x=sqrt((ln(7))/(ln(11))),x=-sqrt((ln(7))/(ln(11)))
Solve for x: 7^{1/x}=11^x
The solution is x=sqrt((ln(7))/(ln(11))),x=-sqrt((ln(7))/(ln(11)))