What is the answer to 6^{n+7}=67 ?

The answer to 6^{n+7}=67 is n=(ln(67))/(ln(6))-7

Solve for n: 6^{n+7}=67

The solution is n=(ln(67))/(ln(6))-7

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6^{n + 7} = 67

n = \frac{ln ( 67 )}{ln ( 6 )} - 7

Decimal

n = - 4.65331 \dots

Solution steps

6^{n + 7} = 67

Apply exponent rules

(n + 7) ln (6) = ln (67)

Solve

(n + 7) ln (6) = ln (67) : n = \frac{ln ( 67 )}{ln ( 6 )} - 7

n = \frac{ln ( 67 )}{ln ( 6 )} - 7

1 2^{5 x} = 3 \cdot 1 5^{3 x}

3^{x - 3} = 1 7^{- 5 x}

9 e^{x} = 3

2^{2 x - 1} = 5^{x + 5}

x, 13 (1 + e^{- x})^{- 1} = 2

What is the answer to 6^{n+7}=67 ?
The answer to 6^{n+7}=67 is n=(ln(67))/(ln(6))-7
Solve for n: 6^{n+7}=67
The solution is n=(ln(67))/(ln(6))-7