What is the answer to 2^x*2^{x-2}=sqrt(2) ?

The answer to 2^x*2^{x-2}=sqrt(2) is x= 5/4

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2^x*2^{x-2}=sqrt(2)

2^{x} \cdot 2^{x - 2} = 2

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

2^{x} \cdot 2^{x - 2} = 2

Apply exponent rules

2 x - 2 = \frac{1}{2}

Solve

2 x - 2 = \frac{1}{2} : x = \frac{5}{4}

x = \frac{5}{4}

4 e^{2 x} = 9

2^{20 x + 10} = 4^{10 x + 5}

7^{x + 4} = 8^{x}

\frac{1}{3 e ^{2 - 3 x} + 3} = 7

7^{3 x^{2}} = 4 9^{6 x + 2}

What is the answer to 2^x*2^{x-2}=sqrt(2) ?
The answer to 2^x*2^{x-2}=sqrt(2) is x= 5/4
Solve for x: 2^x*2^{x-2}=sqrt(2)
The solution is x= 5/4