What is the answer to \sqrt[4]{16^{x+5}}=4^{x+3} ?

The answer to \sqrt[4]{16^{x+5}}=4^{x+3} is x=-1

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\sqrt[4]{16^{x+5}}=4^{x+3}

x = - 1

Solution steps

Apply exponent rules

\frac{1}{2} (x + 5) = x + 3

Solve

\frac{1}{2} (x + 5) = x + 3 : x = - 1

x = - 1

4^{5 x - x^{2}} = 4^{- 6}

5^{x} = 3^{2 x + 1}

x, 0 = e^{2 x} - 3 e^{x} + 2

7^{2 x + 5} = 5 \cdot (3^{3 x})

2^{x} = \frac{4 ^{x - 2}}{8}

What is the answer to \sqrt[4]{16^{x+5}}=4^{x+3} ?
The answer to \sqrt[4]{16^{x+5}}=4^{x+3} is x=-1
Solve for x: \sqrt[4]{16^{x+5}}=4^{x+3}
The solution is x=-1