What are the solutions to the equation x^3-5x^2-x+5=0 ?

The solutions to the equation x^3-5x^2-x+5=0 are x=5,x=-1,x=1

Find the zeros of x^3-5x^2-x+5=0

The zeros of x^3-5x^2-x+5=0 are x=5,x=-1,x=1

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x^{3} - 5 x^{2} - x + 5 = 0

x = 5, x = - 1, x = 1

Solution steps

x^{3} - 5 x^{2} - x + 5 = 0

Factor

x^{3} - 5 x^{2} - x + 5 : (x - 5) (x + 1) (x - 1)

(x - 5) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 5, x = - 1, x = 1

x^{3} + 4 x^{2} - 10 = 0

0 = 2 x^{3} - 4 x^{2}

x^{3} - 6 x^{2} + 9 x = 0

2 x^{3} + 3 x^{2} - 3 x - 2 = 0

0 = x^{3} - 4 x

What are the solutions to the equation x^3-5x^2-x+5=0 ?
The solutions to the equation x^3-5x^2-x+5=0 are x=5,x=-1,x=1
Find the zeros of x^3-5x^2-x+5=0
The zeros of x^3-5x^2-x+5=0 are x=5,x=-1,x=1