What are the solutions to the equation x^3+7x^2-x-7=0 ?

The solutions to the equation x^3+7x^2-x-7=0 are x=-7,x=-1,x=1

Find the zeros of x^3+7x^2-x-7=0

The zeros of x^3+7x^2-x-7=0 are x=-7,x=-1,x=1

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x^{3} + 7 x^{2} - x - 7 = 0

x = - 7, x = - 1, x = 1

Solution steps

x^{3} + 7 x^{2} - x - 7 = 0

Factor

x^{3} + 7 x^{2} - x - 7 : (x + 7) (x + 1) (x - 1)

(x + 7) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - 7, x = - 1, x = 1

- x^{3} - x^{2} + 5 x - 3 = 0

x^{3} = 81 x

2 x^{3} = - 6 x^{2} + x + 3

x^{3} - 5 x = 15 x^{2}

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 = 0

What are the solutions to the equation x^3+7x^2-x-7=0 ?
The solutions to the equation x^3+7x^2-x-7=0 are x=-7,x=-1,x=1
Find the zeros of x^3+7x^2-x-7=0
The zeros of x^3+7x^2-x-7=0 are x=-7,x=-1,x=1