What are the solutions to the equation 0=x^3-1 ?

The solutions to the equation 0=x^3-1 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

Find the zeros of 0=x^3-1

The zeros of 0=x^3-1 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

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0 = x^{3} - 1

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Solution steps

0 = x^{3} - 1

Switch sides

x^{3} - 1 = 0

Move

1

to the right side

x^{3} = 1

For

x^{3} = f (a)

the solutions are

x = 1, x = \frac{- 1 + 3 i}{2}, x = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

x^{4} + 13 x^{3} + 42 x^{2} = 0

x^{3} + 7 x^{2} - 5 x - 35 = 0

x, y^{2} = C x^{3} + 1

h^{4} + 9 = 10 h^{2}

- 3 (36 x^{2} - 25) (x^{2} + 1) = 0

What are the solutions to the equation 0=x^3-1 ?
The solutions to the equation 0=x^3-1 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i
Find the zeros of 0=x^3-1
The zeros of 0=x^3-1 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i