What are the solutions to the equation x^3-4x^2=21x ?

The solutions to the equation x^3-4x^2=21x are x=0,x=-3,x=7

Find the zeros of x^3-4x^2=21x

The zeros of x^3-4x^2=21x are x=0,x=-3,x=7

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x^{3} - 4 x^{2} = 21 x

x = 0, x = - 3, x = 7

Solution steps

x^{3} - 4 x^{2} = 21 x

Move

21 x

to the left side

x^{3} - 4 x^{2} - 21 x = 0

Factor

x^{3} - 4 x^{2} - 21 x : x (x + 3) (x - 7)

x (x + 3) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or x - 7 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = - 3, x = 7

x^{3} - 5 x^{2} + 9 x - 5 = 0

- x^{3} + 7 x^{2} - 16 x + 12 = 0

y^{3} = - 1

y^{3} = - 8

x^{3} - x^{2} - 2 = 3

What are the solutions to the equation x^3-4x^2=21x ?
The solutions to the equation x^3-4x^2=21x are x=0,x=-3,x=7
Find the zeros of x^3-4x^2=21x
The zeros of x^3-4x^2=21x are x=0,x=-3,x=7