What are the solutions to the equation (x+2)(x-1)^2=2 ?

The solutions to the equation (x+2)(x-1)^2=2 are x=0,x=-sqrt(3),x=sqrt(3)

Find the zeros of (x+2)(x-1)^2=2

The zeros of (x+2)(x-1)^2=2 are x=0,x=-sqrt(3),x=sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2) (x - 1)^{2} = 2

x = 0, x = - 3, x = 3

Decimal Notation

x = 0, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

(x + 2) (x - 1)^{2} = 2

Expand

(x + 2) (x - 1)^{2} : x^{3} - 3 x + 2

x^{3} - 3 x + 2 = 2

Move

2

to the left side

x^{3} - 3 x = 0

Factor

x^{3} - 3 x : x (x + 3) (x - 3)

x (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 3, x = 3

x^{3} - 4 x^{2} + 2 x + 1 = 0

x^{4} - 4 x^{3} - 6 x^{2} + 4 x + 5 = 0

x 0.12 x^{2} + 40 x - 32 = 0

1.035 = (1 + \frac{r}{4})^{4}

- x^{3} - x + 2 = 0

What are the solutions to the equation (x+2)(x-1)^2=2 ?
The solutions to the equation (x+2)(x-1)^2=2 are x=0,x=-sqrt(3),x=sqrt(3)
Find the zeros of (x+2)(x-1)^2=2
The zeros of (x+2)(x-1)^2=2 are x=0,x=-sqrt(3),x=sqrt(3)