What are the solutions to the equation (2x-1)^3=27 ?

The solutions to the equation (2x-1)^3=27 are x=2,x=-1/4+i(3sqrt(3))/4 ,x=-1/4-i(3sqrt(3))/4

Find the zeros of (2x-1)^3=27

The zeros of (2x-1)^3=27 are x=2,x=-1/4+i(3sqrt(3))/4 ,x=-1/4-i(3sqrt(3))/4

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(2 x - 1)^{3} = 27

x = 2, x = - \frac{1}{4} + i \frac{3 3}{4}, x = - \frac{1}{4} - i \frac{3 3}{4}

Solution steps

(2 x - 1)^{3} = 27

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 2, x = - \frac{1}{4} + i \frac{3 3}{4}, x = - \frac{1}{4} - i \frac{3 3}{4}

0 = 2 x^{3} - x^{2} - 3 x

3 (x^{2} - 14) (x^{2} + 36) = 0

n^{3} = 10

4 x^{3} + 3 x^{2} - 6 x + 4 = 0

x^{4} - 36 x^{2} = - 35

What are the solutions to the equation (2x-1)^3=27 ?
The solutions to the equation (2x-1)^3=27 are x=2,x=-1/4+i(3sqrt(3))/4 ,x=-1/4-i(3sqrt(3))/4
Find the zeros of (2x-1)^3=27
The zeros of (2x-1)^3=27 are x=2,x=-1/4+i(3sqrt(3))/4 ,x=-1/4-i(3sqrt(3))/4