What are the solutions to the equation 0=x^3-3x^2+x+5 ?

The solutions to the equation 0=x^3-3x^2+x+5 are x=-1,x=2+i,x=2-i

Find the zeros of 0=x^3-3x^2+x+5

The zeros of 0=x^3-3x^2+x+5 are x=-1,x=2+i,x=2-i

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0 = x^{3} - 3 x^{2} + x + 5

x = - 1, x = 2 + i, x = 2 - i

Solution steps

0 = x^{3} - 3 x^{2} + x + 5

Switch sides

x^{3} - 3 x^{2} + x + 5 = 0

Factor

x^{3} - 3 x^{2} + x + 5 : (x + 1) (x^{2} - 4 x + 5)

(x + 1) (x^{2} - 4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} - 4 x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} - 4 x + 5 = 0 : x = 2 + i, x = 2 - i

The solutions are

x = - 1, x = 2 + i, x = 2 - i

(y^{2} - 7)^{2} + 7 (y^{2} - 7) - 18 = 0

k^{3} = 343

2 x^{3} + 72 = 200

18 x^{5} + 6 x^{4} - 24 x^{3} = 6 x^{2}

2 y^{4} + 3 y^{3} - 16 y^{2} + 15 y - 4 = 0

What are the solutions to the equation 0=x^3-3x^2+x+5 ?
The solutions to the equation 0=x^3-3x^2+x+5 are x=-1,x=2+i,x=2-i
Find the zeros of 0=x^3-3x^2+x+5
The zeros of 0=x^3-3x^2+x+5 are x=-1,x=2+i,x=2-i