What are the solutions to the equation 5x^3-9x^2+3x+1=0 ?

The solutions to the equation 5x^3-9x^2+3x+1=0 are x=1,x=-1/5

Find the zeros of 5x^3-9x^2+3x+1=0

The zeros of 5x^3-9x^2+3x+1=0 are x=1,x=-1/5

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5 x^{3} - 9 x^{2} + 3 x + 1 = 0

x = 1, x = - \frac{1}{5}

Solution steps

5 x^{3} - 9 x^{2} + 3 x + 1 = 0

Factor

5 x^{3} - 9 x^{2} + 3 x + 1 : (x - 1)^{2} (5 x + 1)

(x - 1)^{2} (5 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 5 x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

The solutions are

x = 1, x = - \frac{1}{5}

0 = y^{4} - y

- 7 x - 8 + x^{4} = 0

9 x^{3} + 9 = 0

x^{3} + 5 x^{2} + 2 x - 8 = x^{2} + 3 x - 4

(3 w - 21) (w^{2} + 9 w + 20) = 0

What are the solutions to the equation 5x^3-9x^2+3x+1=0 ?
The solutions to the equation 5x^3-9x^2+3x+1=0 are x=1,x=-1/5
Find the zeros of 5x^3-9x^2+3x+1=0
The zeros of 5x^3-9x^2+3x+1=0 are x=1,x=-1/5