What are the solutions to the equation 4x^3-12x^2+9x=0 ?

The solutions to the equation 4x^3-12x^2+9x=0 are x=0,x= 3/2

Find the zeros of 4x^3-12x^2+9x=0

The zeros of 4x^3-12x^2+9x=0 are x=0,x= 3/2

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4 x^{3} - 12 x^{2} + 9 x = 0

x = 0, x = \frac{3}{2}

Decimal Notation

x = 0, x = 1.5

Solution steps

4 x^{3} - 12 x^{2} + 9 x = 0

Factor

4 x^{3} - 12 x^{2} + 9 x : x (2 x - 3)^{2}

x (2 x - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 3 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = \frac{3}{2}

0.16 = (1 + x)^{3} - 1

4 t^{3} + 6 t + 2.5 = 25

3 x^{2} \cdot 2 x = 162

x (x + 2) (x - 4) = 2

x^{4} + 3 x^{3} - 3 x^{2} - 7 x + 6 = 0

What are the solutions to the equation 4x^3-12x^2+9x=0 ?
The solutions to the equation 4x^3-12x^2+9x=0 are x=0,x= 3/2
Find the zeros of 4x^3-12x^2+9x=0
The zeros of 4x^3-12x^2+9x=0 are x=0,x= 3/2