What are the solutions to the equation 12x^4+11x^3-26x^2+x+2=0 ?

The solutions to the equation 12x^4+11x^3-26x^2+x+2=0 are x=1,x=-2,x=-1/4 ,x= 1/3

Find the zeros of 12x^4+11x^3-26x^2+x+2=0

The zeros of 12x^4+11x^3-26x^2+x+2=0 are x=1,x=-2,x=-1/4 ,x= 1/3

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12 x^{4} + 11 x^{3} - 26 x^{2} + x + 2 = 0

x = 1, x = - 2, x = - \frac{1}{4}, x = \frac{1}{3}

Decimal Notation

x = 1, x = - 2, x = - 0.25, x = 0.33333 \dots

Solution steps

12 x^{4} + 11 x^{3} - 26 x^{2} + x + 2 = 0

Factor

12 x^{4} + 11 x^{3} - 26 x^{2} + x + 2 : (x - 1) (x + 2) (4 x + 1) (3 x - 1)

(x - 1) (x + 2) (4 x + 1) (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or 4 x + 1 = 0 or 3 x - 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions are

x = 1, x = - 2, x = - \frac{1}{4}, x = \frac{1}{3}

x, y = (x - 1)^{3}

6 (5 x^{4} - 6 x^{2} + 1) = 0

y^{3} + 0.5 y = 0

6804 = 3780 (1 + r)^{4}

7 + 10 + 63 - 40 + 89 - 88 + 101 - 140 = x^{5}

What are the solutions to the equation 12x^4+11x^3-26x^2+x+2=0 ?
The solutions to the equation 12x^4+11x^3-26x^2+x+2=0 are x=1,x=-2,x=-1/4 ,x= 1/3
Find the zeros of 12x^4+11x^3-26x^2+x+2=0
The zeros of 12x^4+11x^3-26x^2+x+2=0 are x=1,x=-2,x=-1/4 ,x= 1/3