What are the solutions to the equation 3x^5-4x^2-3=0,0<= x<= 2 ?

The solutions to the equation 3x^5-4x^2-3=0,0<= x<= 2 are x\approx 1.25353…

Find the zeros of 3x^5-4x^2-3=0,0<= x<= 2

The zeros of 3x^5-4x^2-3=0,0<= x<= 2 are x\approx 1.25353…

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3 x^{5} - 4 x^{2} - 3 = 0, 0 \leq x \leq 2

x \approx 1.25353 \dots

Solution steps

3 x^{5} - 4 x^{2} - 3 = 0

Find one solution for

3 x^{5} - 4 x^{2} - 3 = 0

using Newton-Raphson:

x \approx 1.25353 \dots

Apply long division:

\frac{3 x ^{5} - 4 x ^{2} - 3}{x - 1.25353 \dots} = 3 x^{4} + 3.76059 \dots x^{3} + 4.71403 \dots x^{2} + 1.90919 \dots x + 2.39323 \dots

3 x^{4} + 3.76059 \dots x^{3} + 4.71403 \dots x^{2} + 1.90919 \dots x + 2.39323 \dots \approx 0

Find one solution for

3 x^{4} + 3.76059 \dots x^{3} + 4.71403 \dots x^{2} + 1.90919 \dots x + 2.39323 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 1.25353 \dots

Check constrains

x \approx 1.25353 \dots

x^{3} + 5 x^{2} - 5 x - 8 = 0

x, x^{3} + y = 5

x^{3} - x^{2} - x \cdot 2^{1} = 0

2 x^{3} - 5 x^{2} - 2 x + 5 = 0

t, (t^{4} - 1)^{2} = x

What are the solutions to the equation 3x^5-4x^2-3=0,0<= x<= 2 ?
The solutions to the equation 3x^5-4x^2-3=0,0<= x<= 2 are x\approx 1.25353…
Find the zeros of 3x^5-4x^2-3=0,0<= x<= 2
The zeros of 3x^5-4x^2-3=0,0<= x<= 2 are x\approx 1.25353…