What are the solutions to the equation x^3-x^2-x*2^1=0 ?

The solutions to the equation x^3-x^2-x*2^1=0 are x=0,x=-1,x=2

Find the zeros of x^3-x^2-x*2^1=0

The zeros of x^3-x^2-x*2^1=0 are x=0,x=-1,x=2

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x^{3} - x^{2} - x \cdot 2^{1} = 0

x = 0, x = - 1, x = 2

Solution steps

x^{3} - x^{2} - x \cdot 2^{1} = 0

Factor

x^{3} - x^{2} - x \cdot 2^{1} : x (x + 1) (x - 2)

x (x + 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 1, x = 2

2 x^{3} - 5 x^{2} - 2 x + 5 = 0

t, (t^{4} - 1)^{2} = x

(1 + x)^{12} = 1.12

(1 + x)^{12} = 1.15

- x^{3} - 36 x^{2} - 416 x - 1552 = 0

What are the solutions to the equation x^3-x^2-x*2^1=0 ?
The solutions to the equation x^3-x^2-x*2^1=0 are x=0,x=-1,x=2
Find the zeros of x^3-x^2-x*2^1=0
The zeros of x^3-x^2-x*2^1=0 are x=0,x=-1,x=2