What are the solutions to the equation 3y^4-5y^3+2y^2=0 ?

The solutions to the equation 3y^4-5y^3+2y^2=0 are y=0,y= 2/3 ,y=1

Find the zeros of 3y^4-5y^3+2y^2=0

The zeros of 3y^4-5y^3+2y^2=0 are y=0,y= 2/3 ,y=1

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3 y^{4} - 5 y^{3} + 2 y^{2} = 0

y = 0, y = \frac{2}{3}, y = 1

Decimal Notation

y = 0, y = 0.66666 \dots, y = 1

Solution steps

3 y^{4} - 5 y^{3} + 2 y^{2} = 0

Factor

3 y^{4} - 5 y^{3} + 2 y^{2} : y^{2} (3 y - 2) (y - 1)

y^{2} (3 y - 2) (y - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 3 y - 2 = 0 or y - 1 = 0

Solve

3 y - 2 = 0 : y = \frac{2}{3}

Solve

y - 1 = 0 : y = 1

The solutions are

y = 0, y = \frac{2}{3}, y = 1

x^{3} - 5 x^{2} - 7 x + 35 = 0

x^{5} + x^{2} = 1

x^{3} = x^{7}

m^{3} = \frac{1}{125}

2 x^{4} + 6 x^{3} - 8 x^{2} - 24 x = 0

What are the solutions to the equation 3y^4-5y^3+2y^2=0 ?
The solutions to the equation 3y^4-5y^3+2y^2=0 are y=0,y= 2/3 ,y=1
Find the zeros of 3y^4-5y^3+2y^2=0
The zeros of 3y^4-5y^3+2y^2=0 are y=0,y= 2/3 ,y=1