What are the solutions to the equation x^3-5x^2-7x+35=0 ?

The solutions to the equation x^3-5x^2-7x+35=0 are x=5,x=-sqrt(7),x=sqrt(7)

Find the zeros of x^3-5x^2-7x+35=0

The zeros of x^3-5x^2-7x+35=0 are x=5,x=-sqrt(7),x=sqrt(7)

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x^{3} - 5 x^{2} - 7 x + 35 = 0

x = 5, x = - 7, x = 7

Decimal Notation

x = 5, x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

x^{3} - 5 x^{2} - 7 x + 35 = 0

Factor

x^{3} - 5 x^{2} - 7 x + 35 : (x - 5) (x + 7) (x - 7)

(x - 5) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 7 = 0 or x - 7 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = 5, x = - 7, x = 7

x^{5} + x^{2} = 1

x^{3} = x^{7}

m^{3} = \frac{1}{125}

2 x^{4} + 6 x^{3} - 8 x^{2} - 24 x = 0

2 x (x^{3} - 216) = 0

What are the solutions to the equation x^3-5x^2-7x+35=0 ?
The solutions to the equation x^3-5x^2-7x+35=0 are x=5,x=-sqrt(7),x=sqrt(7)
Find the zeros of x^3-5x^2-7x+35=0
The zeros of x^3-5x^2-7x+35=0 are x=5,x=-sqrt(7),x=sqrt(7)