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Popular >

x+2=sqrt(r^2-x^2)

Solution

x + 2 = r^{2} - x^{2}

Solution

x = \frac{- 4 + 8 r ^{2} - 16}{4} {r \leq - 2 or r \geq 2}, x = \frac{- 4 - 8 r ^{2} - 16}{4} {- 2 \leq r \leq - 2 or 2 \leq r \leq 2}

Solution steps

x + 2 = r^{2} - x^{2}

Square both sides:

x^{2} + 4 x + 4 = r^{2} - x^{2}

x^{2} + 4 x + 4 = r^{2} - x^{2}

Solve

x^{2} + 4 x + 4 = r^{2} - x^{2} : x = \frac{- 4 + 8 r ^{2} - 16}{4}, x = \frac{- 4 - 8 r ^{2} - 16}{4}

x = \frac{- 4 + 8 r ^{2} - 16}{4}, x = \frac{- 4 - 8 r ^{2} - 16}{4}

Verify Solutions:

x = \frac{- 4 + 8 r ^{2} - 16}{4} {r \leq - 2 or r \geq 2}, x = \frac{- 4 - 8 r ^{2} - 16}{4} {- 2 \leq r \leq - 2 or 2 \leq r \leq 2}

The solutions are

x = \frac{- 4 + 8 r ^{2} - 16}{4} {r \leq - 2 or r \geq 2}, x = \frac{- 4 - 8 r ^{2} - 16}{4} {- 2 \leq r \leq - 2 or 2 \leq r \leq 2}

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x, g^{- 1} (x) = x^{0.5}

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14 = 1 - 4 x + 9

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5 x - 39 - 7 = - 6

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Frequently Asked Questions (FAQ)

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