What is the answer to 2log_{3}(x+4)-log_{3}(9)=2 ?

The answer to 2log_{3}(x+4)-log_{3}(9)=2 is x=5

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2log_{3}(x+4)-log_{3}(9)=2

2 lo g_{3} (x + 4) - lo g_{3} (9) = 2

x = 5

Solution steps

2 lo g_{3} (x + 4) - lo g_{3} (9) = 2

Move

lo g_{3} (9)

to the right side

2 lo g_{3} (x + 4) = 2 + lo g_{3} (9)

Divide both sides by

2

lo g_{3} (x + 4) = \frac{2 + lo g _{3} ( 9 )}{2}

Apply log rules

x + 4 = 9

Solve

x + 4 = 9 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{27} (x) = \frac{1}{3}

lo g_{10} (x) + lo g_{10} (x + 21) = 2

lo g_{2} (x) + lo g_{2} (x - 7) = 3

lo g_{2} (x) + lo g_{4} (x) = 2

lo g_{2} (x + 3) + lo g_{2} (x - 3) = 4

What is the answer to 2log_{3}(x+4)-log_{3}(9)=2 ?
The answer to 2log_{3}(x+4)-log_{3}(9)=2 is x=5
Solve for x: 2log_{3}(x+4)-log_{3}(9)=2
The solution is x=5