What is the answer to log_{2}(x+7)=3-log_{2}(x+5) ?

The answer to log_{2}(x+7)=3-log_{2}(x+5) is x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x+7)=3-log_{2}(x+5)

lo g_{2} (x + 7) = 3 - lo g_{2} (x + 5)

x = - 3

Solution steps

lo g_{2} (x + 7) = 3 - lo g_{2} (x + 5)

Add

lo g_{2} (x + 5)

to both sides

lo g_{2} (x + 7) + lo g_{2} (x + 5) = 3 - lo g_{2} (x + 5) + lo g_{2} (x + 5)

Simplify

lo g_{2} (x + 7) + lo g_{2} (x + 5) = 3

Apply log rules

(x + 7) (x + 5) = 8

Solve

(x + 7) (x + 5) = 8 : x = - 3, x = - 9

x = - 3, x = - 9

Verify Solutions:

x = - 3

True

, x = - 9

False

The solution is

x = - 3

ln (x^{2}) + ln (x) = 8

lo g_{2} (x) + lo g_{4} (8 x) = 6

lo g_{4} (3 x - 7) = 1

lo g_{2} (x) + lo g_{4} (x) = 9

lo g_{2} (y^{3}) = 6

What is the answer to log_{2}(x+7)=3-log_{2}(x+5) ?
The answer to log_{2}(x+7)=3-log_{2}(x+5) is x=-3
Solve for x: log_{2}(x+7)=3-log_{2}(x+5)
The solution is x=-3