What is the answer to log_{2}(x^2-2x)=3 ?

The answer to log_{2}(x^2-2x)=3 is x=4,x=-2

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log_{2}(x^2-2x)=3

lo g_{2} (x^{2} - 2 x) = 3

x = 4, x = - 2

Solution steps

lo g_{2} (x^{2} - 2 x) = 3

Apply log rules

x^{2} - 2 x = 8

Solve

x^{2} - 2 x = 8 : x = 4, x = - 2

x = 4, x = - 2

ln (2 x) = 4 ln (4 x)

ln (- 3 x - 1) - ln (7) = 2

lo g_{5} (x - 3) = 1 - lo g_{5} (x - 7)

2 lo g_{2} (x) - lo g_{2} (2 x) = 3

2 ln (x) = ln (3) + ln (6 - x)

What is the answer to log_{2}(x^2-2x)=3 ?
The answer to log_{2}(x^2-2x)=3 is x=4,x=-2
Solve for x: log_{2}(x^2-2x)=3
The solution is x=4,x=-2