What is the answer to log_{10}(x)+log_{10}(x-48)=2 ?

The answer to log_{10}(x)+log_{10}(x-48)=2 is x=50

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log_{10}(x)+log_{10}(x-48)=2

lo g_{10} (x) + lo g_{10} (x - 48) = 2

x = 50

Solution steps

lo g_{10} (x) + lo g_{10} (x - 48) = 2

Apply log rules

x (x - 48) = 100

Solve

x (x - 48) = 100 : x = 50, x = - 2

x = 50, x = - 2

Verify Solutions:

x = 50

True

, x = - 2

False

The solution is

x = 50

lo g_{7} (x^{2}) = 2

0.678 = ln (x^{2})

2 lo g_{2} (x + 5) - lo g_{2} (x + 9) = 1

x, ln (y) = 2 ln (x)

ln (x) + ln (x + 1) = ln (12)

What is the answer to log_{10}(x)+log_{10}(x-48)=2 ?
The answer to log_{10}(x)+log_{10}(x-48)=2 is x=50
Solve for x: log_{10}(x)+log_{10}(x-48)=2
The solution is x=50