What is the answer to log_{5}(x)+log_{5}(2)=2 ?

The answer to log_{5}(x)+log_{5}(2)=2 is x= 25/2

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log_{5}(x)+log_{5}(2)=2

lo g_{5} (x) + lo g_{5} (2) = 2

x = \frac{25}{2}

Decimal Notation

x = 12.5

Solution steps

lo g_{5} (x) + lo g_{5} (2) = 2

Move

lo g_{5} (2)

to the right side

lo g_{5} (x) = 2 - lo g_{5} (2)

Apply log rules

x = \frac{25}{2}

Verify Solutions:

x = \frac{25}{2}

True

The solution is

x = \frac{25}{2}

lo g_{10} (x + 2) - 2 lo g_{10} (x) = 0

lo g_{10} (x) - lo g_{10} (4) = 2

lo g_{5} (x - 2) + lo g_{5} (x + 2) = 1

lo g_{6} (x + 1) + lo g_{6} (2) = 1

1 + 2 lo g_{4} (t + 1) = 2 lo g_{2} (t)

What is the answer to log_{5}(x)+log_{5}(2)=2 ?
The answer to log_{5}(x)+log_{5}(2)=2 is x= 25/2
Solve for x: log_{5}(x)+log_{5}(2)=2
The solution is x= 25/2