What is the answer to log_{2}(3*2^x-4)=2x-1 ?

The answer to log_{2}(3*2^x-4)=2x-1 is x=2,x=1

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log_{2}(3*2^x-4)=2x-1

lo g_{2} (3 \cdot 2^{x} - 4) = 2 x - 1

x = 2, x = 1

Solution steps

lo g_{2} (3 \cdot 2^{x} - 4) = 2 x - 1

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (3 \cdot 2^{x} - 4)} = 2^{2 x - 1}

Simplify

2^{l o g_{2} (3 \cdot 2^{x} - 4)} : 3 \cdot 2^{x} - 4

3 \cdot 2^{x} - 4 = 2^{2 x - 1}

Solve

3 \cdot 2^{x} - 4 = 2^{2 x - 1} : x = 2, x = 1

x = 2, x = 1

Verify Solutions:

x = 2

True

, x = 1

True

The solutions are

x = 2, x = 1

ln (4 x^{2}) + ln (x) = ln (32)

3 lo g_{10} (x) - 2 = 10

lo g_{3} (x) = lo g_{9} (x + 12)

0 = ln (3 x + 4)

4.2 = - lo g_{10} (x)

What is the answer to log_{2}(3*2^x-4)=2x-1 ?
The answer to log_{2}(3*2^x-4)=2x-1 is x=2,x=1
Solve for x: log_{2}(3*2^x-4)=2x-1
The solution is x=2,x=1