What is the answer to log_{10}(4)+log_{10}(x+4)=1 ?

The answer to log_{10}(4)+log_{10}(x+4)=1 is x=-3/2

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log_{10}(4)+log_{10}(x+4)=1

lo g_{10} (4) + lo g_{10} (x + 4) = 1

x = - \frac{3}{2}

Solution steps

lo g_{10} (4) + lo g_{10} (x + 4) = 1

Move

lo g_{10} (4)

to the right side

lo g_{10} (x + 4) = 1 - lo g_{10} (4)

Apply log rules

x + 4 = \frac{5}{2}

Solve

x + 4 = \frac{5}{2} : x = - \frac{3}{2}

x = - \frac{3}{2}

Verify Solutions:

x = - \frac{3}{2}

True

The solution is

x = - \frac{3}{2}

lo g_{10} (x) (32) = \frac{1}{4}

2 lo g_{10} (x) = 6

lo g_{10} (x - 1) + 2 = ln (x - 1) + 2

ln (lo g_{2} (x)) = 1

lo g_{3} (2 x) + lo g_{3} (4) = 5

What is the answer to log_{10}(4)+log_{10}(x+4)=1 ?
The answer to log_{10}(4)+log_{10}(x+4)=1 is x=-3/2
Solve for x: log_{10}(4)+log_{10}(x+4)=1
The solution is x=-3/2