What is the answer to log_{10}(x)(32)= 1/4 ?

The answer to log_{10}(x)(32)= 1/4 is x=\sqrt[128]{10}

Solve for x: log_{10}(x)(32)= 1/4

The solution is x=\sqrt[128]{10}

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lo g_{10} (x) (32) = \frac{1}{4}

Solution steps

lo g_{10} (x) (32) = \frac{1}{4}

Divide both sides by

32

lo g_{10} (x) = \frac{1}{128}

Apply log rules

Verify Solutions:

True

The solution is

2 lo g_{10} (x) = 6

lo g_{10} (x - 1) + 2 = ln (x - 1) + 2

ln (lo g_{2} (x)) = 1

lo g_{3} (2 x) + lo g_{3} (4) = 5

lo g_{9} (3 - x) = lo g_{3} (x - 1)

What is the answer to log_{10}(x)(32)= 1/4 ?
The answer to log_{10}(x)(32)= 1/4 is x=\sqrt[128]{10}
Solve for x: log_{10}(x)(32)= 1/4
The solution is x=\sqrt[128]{10}