What is the answer to log_{5}(x^2+10x+1)=2 ?

The answer to log_{5}(x^2+10x+1)=2 is x=2,x=-12

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log_{5}(x^2+10x+1)=2

lo g_{5} (x^{2} + 10 x + 1) = 2

x = 2, x = - 12

Solution steps

lo g_{5} (x^{2} + 10 x + 1) = 2

Apply log rules

x^{2} + 10 x + 1 = 25

Solve

x^{2} + 10 x + 1 = 25 : x = 2, x = - 12

x = 2, x = - 12

lo g_{2} (x - 4) + lo g_{2} (x + 3) = 3

lo g_{3} (x^{2} - 6 x + 6) = 0

2 ln (x) = lo g_{e^{3}} (216)

lo g_{3} (x) = lo g_{9} (21)

ln (x + 5) = 1 + ln (x)

What is the answer to log_{5}(x^2+10x+1)=2 ?
The answer to log_{5}(x^2+10x+1)=2 is x=2,x=-12
Solve for x: log_{5}(x^2+10x+1)=2
The solution is x=2,x=-12