What is the answer to log_{4}(1.5x)=log_{16}(3x-1) ?

The answer to log_{4}(1.5x)=log_{16}(3x-1) is x= 2/3

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log_{4}(1.5x)=log_{16}(3x-1)

lo g_{4} (1.5 x) = lo g_{16} (3 x - 1)

x = \frac{2}{3}

Solution steps

lo g_{4} (1.5 x) = lo g_{16} (3 x - 1)

Apply log rules

2.25 x^{2} = 3 x - 1

Solve

2.25 x^{2} = 3 x - 1 : x = \frac{2}{3}

x = \frac{2}{3}

Verify Solutions:

x = \frac{2}{3}

True

The solution is

x = \frac{2}{3}

lo g_{k} (4) = 2

lo g_{10} (3 x) + lo g_{10} (x) 9 = 3

lo g_{2} (3 x + 1) = lo g_{2} (x + 3)

2 lo g_{10} (x - 1) - lo g_{10} (x) = 0

lo g_{2} (4 x - 1) = 3

What is the answer to log_{4}(1.5x)=log_{16}(3x-1) ?
The answer to log_{4}(1.5x)=log_{16}(3x-1) is x= 2/3
Solve for x: log_{4}(1.5x)=log_{16}(3x-1)
The solution is x= 2/3