What is the answer to ln(x-1)+ln(2)=0 ?

The answer to ln(x-1)+ln(2)=0 is x= 3/2

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ln(x-1)+ln(2)=0

ln (x - 1) + ln (2) = 0

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

ln (x - 1) + ln (2) = 0

Move

ln (2)

to the right side

ln (x - 1) = - ln (2)

Apply log rules

x - 1 = \frac{1}{2}

Solve

x - 1 = \frac{1}{2} : x = \frac{3}{2}

x = \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

The solution is

x = \frac{3}{2}

lo g_{2} (x + 2) + lo g_{2} (4) = 4

lo g_{16} (x) = - 4^{- 1}

ln (x - 2) = 6

lo g_{2} (y^{3}) - lo g_{2} (y) = 8

2 ln (7 x + 6) - 2 = 12