What is the answer to log_{2}(x+2)+log_{2}(4)=4 ?

The answer to log_{2}(x+2)+log_{2}(4)=4 is x=2

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log_{2}(x+2)+log_{2}(4)=4

lo g_{2} (x + 2) + lo g_{2} (4) = 4

x = 2

Solution steps

lo g_{2} (x + 2) + lo g_{2} (4) = 4

Move

lo g_{2} (4)

to the right side

lo g_{2} (x + 2) = 4 - lo g_{2} (4)

Apply log rules

x + 2 = 4

Solve

x + 2 = 4 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{16} (x) = - 4^{- 1}

ln (x - 2) = 6

lo g_{2} (y^{3}) - lo g_{2} (y) = 8

2 ln (7 x + 6) - 2 = 12

2 lo g_{3} (x - 4) = lo g_{3} (x + 2) + 1

What is the answer to log_{2}(x+2)+log_{2}(4)=4 ?
The answer to log_{2}(x+2)+log_{2}(4)=4 is x=2
Solve for x: log_{2}(x+2)+log_{2}(4)=4
The solution is x=2