What is the answer to log_{2}(y^3)-log_{2}(y)=8 ?

The answer to log_{2}(y^3)-log_{2}(y)=8 is y=16

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log_{2}(y^3)-log_{2}(y)=8

lo g_{2} (y^{3}) - lo g_{2} (y) = 8

y = 16

Solution steps

lo g_{2} (y^{3}) - lo g_{2} (y) = 8

Apply log rules

y = 16

Verify Solutions:

y = 16

True

The solution is

y = 16

2 ln (7 x + 6) - 2 = 12

2 lo g_{3} (x - 4) = lo g_{3} (x + 2) + 1

lo g_{10} (81) = 4 lo g_{10} (x)

lo g_{10} (1 - k) = - \frac{0.3}{8}

lo g_{b} (3) = 1

What is the answer to log_{2}(y^3)-log_{2}(y)=8 ?
The answer to log_{2}(y^3)-log_{2}(y)=8 is y=16
Solve for y: log_{2}(y^3)-log_{2}(y)=8
The solution is y=16