What is the answer to log_{16}(x)=-4^{-1} ?

The answer to log_{16}(x)=-4^{-1} is x= 1/2

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log_{16}(x)=-4^{-1}

lo g_{16} (x) = - 4^{- 1}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

lo g_{16} (x) = - 4^{- 1}

Apply log rules

x = \frac{1}{2}

ln (x - 2) = 6

lo g_{2} (y^{3}) - lo g_{2} (y) = 8

2 ln (7 x + 6) - 2 = 12

2 lo g_{3} (x - 4) = lo g_{3} (x + 2) + 1

lo g_{10} (81) = 4 lo g_{10} (x)

What is the answer to log_{16}(x)=-4^{-1} ?
The answer to log_{16}(x)=-4^{-1} is x= 1/2
Solve for x: log_{16}(x)=-4^{-1}
The solution is x= 1/2