What is the answer to 2log_{3}(x-4)=log_{3}(x+2)+1 ?

The answer to 2log_{3}(x-4)=log_{3}(x+2)+1 is x=10

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2log_{3}(x-4)=log_{3}(x+2)+1

2 lo g_{3} (x - 4) = lo g_{3} (x + 2) + 1

x = 10

Solution steps

2 lo g_{3} (x - 4) = lo g_{3} (x + 2) + 1

Apply log rules

(x - 4)^{2} = (x + 2) \cdot 3

Solve

(x - 4)^{2} = (x + 2) \cdot 3 : x = 10, x = 1

x = 10, x = 1

Verify Solutions:

x = 10

True

, x = 1

False

The solution is

x = 10

lo g_{10} (81) = 4 lo g_{10} (x)

lo g_{10} (1 - k) = - \frac{0.3}{8}

lo g_{b} (3) = 1

lo g_{16} (36) = 1 - lo g_{4} (x)

n - 8 lo g_{10} (n) = 0

What is the answer to 2log_{3}(x-4)=log_{3}(x+2)+1 ?
The answer to 2log_{3}(x-4)=log_{3}(x+2)+1 is x=10
Solve for x: 2log_{3}(x-4)=log_{3}(x+2)+1
The solution is x=10