What is the answer to ln(x-1)-ln(6-x)=0 ?

The answer to ln(x-1)-ln(6-x)=0 is x= 7/2

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ln(x-1)-ln(6-x)=0

ln (x - 1) - ln (6 - x) = 0

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

ln (x - 1) - ln (6 - x) = 0

Add

ln (6 - x)

to both sides

ln (x - 1) - ln (6 - x) + ln (6 - x) = 0 + ln (6 - x)

Simplify

ln (x - 1) = ln (6 - x)

Apply log rules

x - 1 = 6 - x

Solve

x - 1 = 6 - x : x = \frac{7}{2}

x = \frac{7}{2}

Verify Solutions:

x = \frac{7}{2}

True

The solution is

x = \frac{7}{2}

lo g_{6} (25) = 2 lo g_{6} (x)

ln ((x - 2) (x - \frac{1}{2})) = 0

lo g_{2} (x - 5) + lo g_{2} (x + 5) = 5

4 - lo g_{2} (1 - 3 x) = 3

2 x^{2} = \frac{x ^{2}}{ln ( x )}

What is the answer to ln(x-1)-ln(6-x)=0 ?
The answer to ln(x-1)-ln(6-x)=0 is x= 7/2
Solve for x: ln(x-1)-ln(6-x)=0
The solution is x= 7/2