What is the answer to log_{2}(7x-2)-log_{2}(3)=5 ?

The answer to log_{2}(7x-2)-log_{2}(3)=5 is x=14

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log_{2}(7x-2)-log_{2}(3)=5

lo g_{2} (7 x - 2) - lo g_{2} (3) = 5

x = 14

Solution steps

lo g_{2} (7 x - 2) - lo g_{2} (3) = 5

Move

lo g_{2} (3)

to the right side

lo g_{2} (7 x - 2) = 5 + lo g_{2} (3)

Apply log rules

7 x - 2 = 96

Solve

7 x - 2 = 96 : x = 14

x = 14

Verify Solutions:

x = 14

True

The solution is

x = 14

lo g_{3} (2 x) = 1 - lo g_{3} (x)

lo g_{5} (5^{x} - 20) = 3 - x

2 lo g_{2} (x) = lo g_{2} (x + 12) + 1

v, ln (p) + R ln (v) = C

lo g_{y} (125) = 3

What is the answer to log_{2}(7x-2)-log_{2}(3)=5 ?
The answer to log_{2}(7x-2)-log_{2}(3)=5 is x=14
Solve for x: log_{2}(7x-2)-log_{2}(3)=5
The solution is x=14