What is the answer to log_{3}(6x-7)=2 ?

The answer to log_{3}(6x-7)=2 is x= 8/3

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log_{3}(6x-7)=2

lo g_{3} (6 x - 7) = 2

x = \frac{8}{3}

Solution steps

lo g_{3} (6 x - 7) = 2

Apply log rules

6 x - 7 = 9

Solve

6 x - 7 = 9 : x = \frac{8}{3}

x = \frac{8}{3}

lo g_{4} (3 x + 1) = 3

lo g_{3} (x + 6) + lo g_{3} (x + 4) = 1

6 - 2 ln (x) = 7

lo g_{4} (\frac{x - 2}{2 x + 3}) = 0

lo g_{10} (x) + lo g_{10} (80) = 3