What is the answer to 3.28=-log_{10}(x) ?

The answer to 3.28=-log_{10}(x) is x= 1/(10^{3.28)}

Solve for x: 3.28=-log_{10}(x)

The solution is x= 1/(10^{3.28)}

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3.28 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{3.28}}

Solution steps

3.28 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

3.28 + lo g_{10} (x) = 0

Move

3.28

to the right side

lo g_{10} (x) = - 3.28

Apply log rules

x = \frac{1}{1 0 ^{3.28}}

Verify Solutions:

x = \frac{1}{1 0 ^{3.28}}

True

The solution is

x = \frac{1}{1 0 ^{3.28}}

lo g_{3} (x + 3) - lo g_{3} (x + 1) = 1

lo g_{3} (x) = 4 lo g_{10} (x) 3

lo g_{x} (10) = \frac{1}{2}

x, lo g_{x} (64) = 2

lo g_{2 x^{2}} (x^{3} + x) = 1

What is the answer to 3.28=-log_{10}(x) ?
The answer to 3.28=-log_{10}(x) is x= 1/(10^{3.28)}
Solve for x: 3.28=-log_{10}(x)
The solution is x= 1/(10^{3.28)}