What is the answer to log_{3}(2x)-log_{3}(x+1)=1 ?

The answer to log_{3}(2x)-log_{3}(x+1)=1 is No Solution for x\in\mathbb{R}

Solve for x: log_{3}(2x)-log_{3}(x+1)=1

The solution is No Solution for x\in\mathbb{R}

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lo g_{3} (2 x) - lo g_{3} (x + 1) = 1

No Solution for x \in R

Solution steps

lo g_{3} (2 x) - lo g_{3} (x + 1) = 1

Add

lo g_{3} (x + 1)

to both sides

lo g_{3} (2 x) - lo g_{3} (x + 1) + lo g_{3} (x + 1) = 1 + lo g_{3} (x + 1)

Simplify

lo g_{3} (2 x) = 1 + lo g_{3} (x + 1)

Apply log rules

2 x = 3 (x + 1)

Solve

2 x = 3 (x + 1) : x = - 3

x = - 3

Verify Solutions:

x = - 3

False

The solution is

No Solution for x \in R

ln (- 1 + c) = ln (2)

x, ln (x + 3) - ln (x + 2) = 4

8 lo g_{2} (x) = 3

ln (x) + ln (x + 4) = ln (3 x + 12)

lo g_{4} (1 + x^{2}) = 0.5

What is the answer to log_{3}(2x)-log_{3}(x+1)=1 ?
The answer to log_{3}(2x)-log_{3}(x+1)=1 is No Solution for x\in\mathbb{R}
Solve for x: log_{3}(2x)-log_{3}(x+1)=1
The solution is No Solution for x\in\mathbb{R}