What is the answer to solvefor x,ln(x+3)-ln(x+2)=4 ?

The answer to solvefor x,ln(x+3)-ln(x+2)=4 is x=(2e^4-3)/(1-e^4)

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solvefor x,ln(x+3)-ln(x+2)=4

solve for

x, ln (x + 3) - ln (x + 2) = 4

x = \frac{2 e ^{4} - 3}{1 - e ^{4}}

Decimal Notation

x = - 1.98134 \dots

Solution steps

ln (x + 3) - ln (x + 2) = 4

Add

ln (x + 2)

to both sides

ln (x + 3) - ln (x + 2) + ln (x + 2) = 4 + ln (x + 2)

Simplify

ln (x + 3) = 4 + ln (x + 2)

Apply log rules

x + 3 = e^{4} (x + 2)

Solve

x + 3 = e^{4} (x + 2) : x = \frac{2 e ^{4} - 3}{1 - e ^{4}}

x = \frac{2 e ^{4} - 3}{1 - e ^{4}}

Verify Solutions:

x = \frac{2 e ^{4} - 3}{1 - e ^{4}}

True

The solution is

x = \frac{2 e ^{4} - 3}{1 - e ^{4}}

8 lo g_{2} (x) = 3

ln (x) + ln (x + 4) = ln (3 x + 12)

lo g_{4} (1 + x^{2}) = 0.5

lo g_{3} (7 x) - lo g_{3} (2) = 5

lo g_{2} (3 - x) + lo g_{2} (- x) = 2

What is the answer to solvefor x,ln(x+3)-ln(x+2)=4 ?
The answer to solvefor x,ln(x+3)-ln(x+2)=4 is x=(2e^4-3)/(1-e^4)