What is the answer to ln(x)+ln(x+4)=ln(3x+12) ?

The answer to ln(x)+ln(x+4)=ln(3x+12) is x=3

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ln(x)+ln(x+4)=ln(3x+12)

ln (x) + ln (x + 4) = ln (3 x + 12)

x = 3

Solution steps

ln (x) + ln (x + 4) = ln (3 x + 12)

Apply log rules

x (x + 4) = 3 x + 12

Solve

x (x + 4) = 3 x + 12 : x = 3, x = - 4

x = 3, x = - 4

Verify Solutions:

x = 3

True

, x = - 4

False

The solution is

x = 3

lo g_{4} (1 + x^{2}) = 0.5

lo g_{3} (7 x) - lo g_{3} (2) = 5

lo g_{2} (3 - x) + lo g_{2} (- x) = 2

lo g_{b} (9) = - \frac{1}{3}

- lo g_{10} (x) = 2.8

What is the answer to ln(x)+ln(x+4)=ln(3x+12) ?
The answer to ln(x)+ln(x+4)=ln(3x+12) is x=3
Solve for x: ln(x)+ln(x+4)=ln(3x+12)
The solution is x=3