What is the answer to log_{4}(1+x^2)=0.5 ?

The answer to log_{4}(1+x^2)=0.5 is x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(1+x^2)=0.5

lo g_{4} (1 + x^{2}) = 0.5

x = 1, x = - 1

Solution steps

lo g_{4} (1 + x^{2}) = 0.5

Apply log rules

1 + x^{2} = 2

Solve

1 + x^{2} = 2 : x = 1, x = - 1

x = 1, x = - 1

lo g_{3} (7 x) - lo g_{3} (2) = 5

lo g_{2} (3 - x) + lo g_{2} (- x) = 2

lo g_{b} (9) = - \frac{1}{3}

- lo g_{10} (x) = 2.8

- lo g_{10} (x) = 2.1

What is the answer to log_{4}(1+x^2)=0.5 ?
The answer to log_{4}(1+x^2)=0.5 is x=1,x=-1
Solve for x: log_{4}(1+x^2)=0.5
The solution is x=1,x=-1