What is the answer to log_{x}(2x^2-9x+20)=2 ?

The answer to log_{x}(2x^2-9x+20)=2 is x=5,x=4

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log_{x}(2x^2-9x+20)=2

lo g_{x} (2 x^{2} - 9 x + 20) = 2

x = 5, x = 4

Solution steps

lo g_{x} (2 x^{2} - 9 x + 20) = 2

Apply log rules

\frac{ln ( 2 x ^{2} - 9 x + 20 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( 2 x ^{2} - 9 x + 20 )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (2 x^{2} - 9 x + 20) = 2 ln (x)

Apply log rules

2 x^{2} - 9 x + 20 = x^{2}

Solve

2 x^{2} - 9 x + 20 = x^{2} : x = 5, x = 4

x = 5, x = 4

Verify Solutions:

x = 5

True

, x = 4

True

The solutions are

x = 5, x = 4

v, w = lo g_{4} (2 v + 3)

ln (x^{3} + 2000) = 2

lo g_{2} (4 x) + lo g_{2} (2) = 4

ln (5) = 1 + ln (2 x)

2 ln (x - 1) - ln (x) = 1

What is the answer to log_{x}(2x^2-9x+20)=2 ?
The answer to log_{x}(2x^2-9x+20)=2 is x=5,x=4
Solve for x: log_{x}(2x^2-9x+20)=2
The solution is x=5,x=4